MCQ
Which of the following compounds react with $NaHCO _3$ :
- A$CH _3 OH$
- B
- ✓$CH _3 COOH$
- DAll of these
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Given $: \frac{2.303 RT }{ F }=0.06 V$
$Pd _{( aq )}^{2+}+2 e ^{-} \rightleftharpoons Pd ( s ) \quad E ^{\circ}=0.83\,V$
$PdCl _4^{2-}( aq )+2 e ^{-} \rightleftharpoons Pd ( s )+4 Cl ^{-}( aq )$
$E ^{\circ}=0.65\,V$
$0.48 + \log \left\{ { - \frac{{d[A]}}{{dt}}} \right\} = \log \left\{ { + \frac{{d[B]}}{{dt}}} \right\} + 0.7$
Then, $x : y$ is