MCQ
Which of the following differential equations has $y=c_{1} e^{x}+c_{2} e^{-x}$ as the general solution?
  • $\frac{d^{2} y}{d x^{2}}-y=0$
  • B
    $\frac{d^{2} y}{d x^{2}}+y=0$
  • C
    $\frac{d^{2} y}{d x^{2}}+1=0$
  • D
    $\frac{d^{2} y}{d x^{2}}-1=0$

Answer

Correct option: A.
$\frac{d^{2} y}{d x^{2}}-y=0$
a
The given equation is :

$y=c_{1} e^{x}+c_{2} e^{x}$        .........$(1)$

Differentiating with respect to $\mathrm{x}$, we get:

$\frac{d y}{d x}=c_{1} e^{x}-c_{2} e^{-x}$

Again, differentiating with respect to $\mathrm{x}$, we get:

$\frac{d^{2} y}{d x^{2}}=c_{1} e^{x}+c_{2} e^{-x}$

$\Rightarrow \frac{d^{2} y}{d x^{2}}=y$

$\Rightarrow \frac{d^{2} y}{d x^{2}}-y=0$

This is the required differential equation of the given equation of curve.

Hence, the correct answer is $\mathrm{A}$.

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