MCQ
Which of the following does not contain any co- ordinate bond?
  • A
    $H_3O^+$
  • B
    $BF^-_4$
  • $HF^-_2$
  • D
    $NH^+_4$

Answer

Correct option: C.
$HF^-_2$
c
In option $A$, coordinate$/$dative bond is formed between lone pair of Oxygen atom and empty s orbital of $H$ ion.

In option $B$, Boron atom has empty $2 p$ orbital after formation of $BF _3$, so it can accept lone pair of fluorine atom ($F$ atom has $3$ lone pairs) and form $BF^{-} _4$.

In option $C$, there is no coordinate bonding but very strong Hydrogen bonding due to high electronegativity of Fluorine. $(C)$ is the correct answer.

In option $D$, Nitrogen has one lone pair left after forming $3$ covalent bonds with hydrogen, it forms coordinate bond by sharing that lone pair with $H$ ion.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free