MCQ
Which of the following expression is true for an ideal gas.
  • A
    ${\left( {\frac{{\partial V}}{{\partial T}}} \right)_p} = 0$
  • B
    ${\left( {\frac{{\partial P}}{{\partial T}}} \right)_V} = 0$
  • ${\left( {\frac{{\partial U}}{{\partial V}}} \right)_T} = 0$
  • D
    ${\left( {\frac{{\partial U}}{{\partial T}}} \right)_V} = 0$

Answer

Correct option: C.
${\left( {\frac{{\partial U}}{{\partial V}}} \right)_T} = 0$
c
For an ideal gas

$\Delta U = nC _{ v } \Delta T$

$PV = nRT$

Now,

$P \frac{\partial V }{\partial T }= nR \frac{\partial T }{\partial T }$

$\left(\frac{\partial V }{\partial T }\right)_{ P }=\frac{ nR }{ P }$

Again, $\frac{\partial P }{\partial T } V = nR \frac{\partial T }{\partial T }$

$\left(\frac{\partial P }{\partial T }\right) V =\frac{ nR }{ V }$

Again, $\Delta U = nC _{ v } \Delta T$

$\left(\frac{\partial U }{\partial V }\right)_{ T }=\frac{\partial\left( n C _{ V } \Delta T \right)}{\partial V }=0$

$\left(\frac{\partial U }{\partial T }\right)_{ T }=\frac{\partial\left( nC _{ V } \Delta T \right)}{\partial T }= nC _{ V }$

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