Correct option: C.${\left( {\frac{{\partial U}}{{\partial V}}} \right)_T} = 0$
c
For an ideal gas
$\Delta U = nC _{ v } \Delta T$
$PV = nRT$
Now,
$P \frac{\partial V }{\partial T }= nR \frac{\partial T }{\partial T }$
$\left(\frac{\partial V }{\partial T }\right)_{ P }=\frac{ nR }{ P }$
Again, $\frac{\partial P }{\partial T } V = nR \frac{\partial T }{\partial T }$
$\left(\frac{\partial P }{\partial T }\right) V =\frac{ nR }{ V }$
Again, $\Delta U = nC _{ v } \Delta T$
$\left(\frac{\partial U }{\partial V }\right)_{ T }=\frac{\partial\left( n C _{ V } \Delta T \right)}{\partial V }=0$
$\left(\frac{\partial U }{\partial T }\right)_{ T }=\frac{\partial\left( nC _{ V } \Delta T \right)}{\partial T }= nC _{ V }$