- A$(C{H_3}){_2}CH - OH$
- ✓${(C{H_3})_3}C - OH$
- C$C{H_3} - C{H_2} - OH$
- D$C{H_3} - C{H_2} - O - C{H_2} - C{H_3}$
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$X$ (Major product) $\xrightarrow{HN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}}Y$ (Major product) $\xrightarrow{Sn\,\,+\,\,HCl}\,Z\,\xrightarrow[S{{O}_{3}}]{}W$
$W$ is
$(i)$ $H_{(aq)}^+ + OH^-= H_2O_{(l)} ,$ $\Delta H = -X_1\,kJ \,mol^{-1}$
$(ii)$ $H_{2(g)} + \frac{1}{2}O_{2(g)} = H_2O_{(l)},$ $\Delta H = -X_2\,kJ \,mol^{-1}$
$(iii)$ $CO_{2(g)} + H_{2(g)} = CO_{(g)} + H_2O_{(l)},$ $\Delta H = -X_3\, kJ\, mol^{-1}$
$(iv)$ $ C_2H_{2(g)}+ \frac{5}{2} O_{2(g)} = 2CO_{2(g)} + H_2O_{(l)},$ $\Delta H = -X_4\,kJ \,mol^{-1}$
Enthalpy of formation of $H_2O_{(l)}$ is

Here $W, Y$ and $Z$ are left, up and right elements with respect to the element $'X'$ and $'X'$ belongs to $16^{th}$ group and $3^{rd}$ period. Then according to given information the incorrect statement regarding given elements is