- ✓$Mn$ $(II)$
- B$Fe$ $(II)$
- C$Co$ $(II)$
- D$Ni$ $(II)$
$5$ unpaired element in $d-$ subshell so it has highest paramagnetic.
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$Z{n^{2 + }} + 2e \to Zn,{E^o} = - 0.762\,V$
$M{g^{2 + }} + 2e \to Mg,{E^o} = - 2.37\,V$
When zinc dust is added to the solution of $MgC{l_2}$
${\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
$[X]$ $\xrightarrow{{KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{HOOC - {{(C{H_2})}_3} - CH - COOH}
\end{array}}
\end{array}}
\end{array}$
$[X]$ will be:

$1-$ Bromopropane is reacted with reagents in List $I$ to give product in List $II$
| List$I-$ Reagent | List$II-$Product |
| $A$ $KOH (\text { alc) }$ | $I$ Nitrile |
| $B$ $KCN \text { (alc) }$ | $II$ Ester |
| $C$ $AgNO _2$ | $III$ Alkene |
| $D$ $H _3 CCOOAg$ | $IV$ Nitroalkane |