- A$H_2O$
- B$F_2O$
- ✓$Cl_2O$
- D$H_2S$
Oxygen difluoride is a chemical element having the symbol $F_2 O$. The bond angle of water is equal to $102^{\circ}$ and it does not have the largest bond angle. Hence, option $(B)$ is incorrect.
Among the given compounds, the $Cl _2 O$ has the largest bond angle and which is equal to $109.5^{\circ}$. The largest bond angle of chlorine monoxide is because of the presence of large lone pair - bond pair repulsion. And it will increase the bond angle of chlorine monoxide. And this type of repulsion also depends upon the electronegativity. Hence, option $(C)$ is correct.
Hydrogen sulphide is a chemical element having the symbol $H _2 S$. The bond angle of water is equal to $90^{\circ}$ and it does not have the largest bond angle. Hence, option $(D)$ is incorrect.
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$HC \equiv CH\mathop {\xrightarrow{{30\%\, {H_2}S{O_4}}}}\limits_{HgS{O_4}} A\xrightarrow{{NaOH}}B$


$\gamma_{1} A +\gamma_{2} B \rightarrow \gamma_{3} C +\gamma_{4} D$
Concentration of $C$ changes from $10\, mmol$ appearance of $D$ is $1.5$ times the rate of disappearance of $B$ which is twice the rate of disappearance $A$. The rate of appearance of $D$ has been experimentally determined to be $9 \,m\,mol$ $dm ^{-3} s ^{-1}$. Therefore the rate of reaction is $......\,m\,mol\, dm ^{-3} \,s ^{-1}$. (Nearest Integer)
[$A$] The work done on the gas is maximum when it is compressed irreversibly from ( $\mathrm{p}_2, \mathrm{~V}_2$ ) to ( $\mathrm{p}_1, \mathrm{~V}_1$ ) against constant pressure $\mathrm{pl}_1$
[$B$] The work done by the gas is less when it is expanded reversibly from $V_1$ to $V_2$ under adiabatic conditions as compared to that when expanded reversibly from $V_1$ to $V_2$ under isothermal conditions
[$C$] The change in internal energy of the gas is ($i$) zero, if it is expanded reversibly with $T_1=T_2$, and ($ii$) positive, if it is expanded reversibly under adiabatic conditions with $T_1 \neq T_2$
[$D$] If the expansion is carried out freely, it is simultaneously both isothermal as well as adiabatic