- A$2\;g$ atom of nitrogen
- ✓$3 \times {10^{23}}$ atoms of $C$
- C$1$ mole of $S$
- D$7.0\;g$ of $Ag$
$(b)$ $6 \times {10^{23}}$ atoms of $C$ has mass $ = 12\,gm$
$3 \times {10^{23}}$ atoms of $C$ has mass $ = \frac{{12 \times 3 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 6\,gm$
$(c)$ $1$ mole of $S$ has mass $= 32\,gm$
$(d)$ $7.0\,gm$ of $Ag$
So, lowest mass = $6\,gm$ of $C$.
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$(i)$ $CH_3CH_2COCH_2Cl$ $(ii)$ $C_6H_5COCH_3$
$(iii)$ $C_6H_5COCHCl_2$ $(iv)$ $CH_3CH_2COCCl_3$

$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}$
If $72 \mathrm{mmol}$ of $\mathrm{PbCl}_2$ is mixed with $50 \mathrm{mmol}$ of$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4$, then amount of $\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2$ formed is......... mmol. (nearest integer)