Question
Which of the following has minimum ionization energy
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$P : 10\ ml, 0.1\ M\ NaOH + 5\ ml, 0.1\ M\ HCl$
$Q : 10\ ml, 0.1\ M\ NaOH + 15\ ml, 0.1\ M\ CH_3COOH$
$R : 10\ ml, 0.1\ M\ NH_3 + 10\ ml, 0.1\ M\ NH_4Cl$
$S : 10\ ml, 0.05\ M\ NaF + 5\ ml, 0.1\ M\ HF$
Which of above solutions act as buffer
| Period number | Group number | |
| $P$ | $2$ | $15$ |
| $Q$ | $3$ | $2$ |
Then formula of the compound formed by $P$ and $Q$ element is