MCQ
Which of the following has terminating decimal expansion ?
- A$\frac{32}{91}$
- ✓$\frac{19}{80}$
- C$\frac{23}{45}$
- D$\frac{25}{42}$
✓
Answer
Correct option: B.
$\frac{19}{80}$
A number is a terminating decimal, if the denominator is of the form $2^m \times 5^n,$
where $m$ and $n$ are non $-$ negative integers.
$\frac{32}{91}=\frac{32}{7\times13}$
$\frac{19}{80}=\frac{19}{2^4\times5}$
$\frac{23}{45}=\frac{23}{3^2\times5}$
$\frac{25}{42}=\frac{25}{2\times3\times7}$
Clearly, option $(b)$ is a terminating decimal, since its denominator is of the form $2^m \times 5^n$
where $m$ and $n$ are non $-$ negative integers.
$\frac{32}{91}=\frac{32}{7\times13}$
$\frac{19}{80}=\frac{19}{2^4\times5}$
$\frac{23}{45}=\frac{23}{3^2\times5}$
$\frac{25}{42}=\frac{25}{2\times3\times7}$
Clearly, option $(b)$ is a terminating decimal, since its denominator is of the form $2^m \times 5^n$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In $\triangle A B C, D$ and $E$ are points on side $A B$ and $A C$ respectively such that $D E \| B C$ and $A D: D B=3: 1$. If $E A=3.3 cm$, then $A C=$
→A piggy bank contains $100$ fifty paise coins, $50$ one rupee coins, $20$ two rupee coins and $10$ five rupee coins. One coin is drawn at random. The probability that the coin drawn will not be a five rupee coin is :
→The median of first 10 prime numbers is:
In given figure, $P Q \| B C$. Find $A B \ ($in $\ cm).$
→ If points (1, 2), (-5, 6) and (a, -2) are collinear, then a =
The $\text{HCF}$ of $867$ and $255$ is :
→The line represented by $4 x-3 y=9$ intersects the $y$-axis at
→If the sum of the roots of a quadratic equation is 6 and their product is 6 , the equation is.
In the given figure,$ \triangle\text{ABC}$ is right-angled at B, such that BC = 6cm and AB = 8cm. A circle with centre O has been inscribed in the triangle. $\text{OP} \perp \text{AB}, \text{OQ} \perp \text{BC} $ and $\text{OR} \perp \text{AC}.$ If OP = OQ = OR = x cm, then x =?
→If $\alpha, \beta$ are the zeros of the polynomial $f(x)=x^2-p(x+1)-c$ such that $(\alpha+1)(\beta+1)=0$, then $c=$
→