- A$CO_3^ - $
- ✓$NH_4^ + $
- C${K_4}[Fe{(CN)_6}]$
- DNone of these
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$6CO_2 + 6H_2O + solar energy \to C_6H_{12}O_6+6O_2$
A blue whales gain $75\ kg$ of mass per day by feeding on krill. The whale must consume ten times this mass of krill each day. The krill must consume $10.0\ kg$ of diatoms to produce $1.0\ kg$ of krill. Assuming that the mass gain of a whale's life is due to the consumption of carbohydrates $(C_6H_{12}O_6)$ , calculate the moles of $CO_2$ that must be used by the diatoms to produce the carbohydrates consumed by a blue whale in a day
$2HI_{(g)} \to H_{2(g)} + I_{2(g)}$
is $200 \frac {KJ}{mol}$ at $600 \,K$. Calculate the fraction of molecules of reactant having energy equal to or greater than activation energy ?

| List $I$(Quantum Number) | List $II$(Information provided) |
| $A$. mı | $I$. Shape of orbital |
| $B$. $m_s$ | $II$. Size of orbital |
| $C$. $1$ | $III$. Orientation of orbital |
| $D$. $\mathrm{n}$ | $IV$. Orientation of spin of electron |
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