- AAcetone
- BDiethyl ether
- CMethanol
- ✓Ethanol
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proteins $\xrightarrow{{enzyme{\text{ }}\left( A \right)}}$ polypeptides $\xrightarrow{{enzyme{\text{ }}\left( B \right)}}$ amino acids,
are respectively
$E^o (Fe^{+2}, Fe) = -0.44$ $ V$
$E^o (Zn^{+2}, Zn) = -0.76$ $ V$
$E^o (Cu^{+2}, Cu) = +0.34$ $V$
$E^o (Cr^{+2}, Cr) = -0.74$ $V$
$E^o (H^+, 1/2H_2) = -0.00$ $V$
${\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \quad\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}, \quad\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
[Given atomic numbers: $\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Fe}=26$,
$\mathrm{Ni}=28, \mathrm{Cu}=29]$
$2NO(g) + 2{H_2}(g) \to {N_2}(g) + 2{H_2}O(g)$ is :
Step $1$ : $2NO(g) + {H_2}(g)\xrightarrow{{slow}}{N_2} + {H_2}{O_2}$
Step : $2$ ${H_2}{O_2} + {H_2}\xrightarrow{{fast}}2{H_2}O$
Then the correct statement is