STD 12 - 4. d and f- block elements — JEE STD 11 Science — Question

$(A)$ Homolytic bond cleavage

$(B)$ Heterolytic bond cleavage

$(C)$ Free radical formation

$(D)$ Primary free radical

$(E)$ Secondary free radical

Choose the correct answer from the options given below:

$\Delta_{f} \mathrm{H}^{\ominus}$ for $\mathrm{KCl}=-436.7 \,\mathrm{~kJ}\, \mathrm{~mol}^{-1}$

$\Delta_{\text {sub }} \mathrm{H}^{\ominus}$ for $\mathrm{K}=89.2 \,\mathrm{~kJ}\, \mathrm{~mol}^{-1}$

$\Delta_{\text {ionization }} \,\mathrm{H}^{-}$ for $\mathrm{K}=419.0\, \mathrm{~kJ}\, \mathrm{~mol}^{-1}$

$\Delta_{\text {electron gain }} \mathrm{H}^{\ominus}$ for $\mathrm{Cl}_{(\text {e) }}=-348.6 \,\mathrm{~kJ} \,\mathrm{~mol}^{-1}$

$\Delta_{\mathrm{bond}} \mathrm{H}^{-}$ for $\mathrm{Cl}_{2}=243.0 \,\mathrm{~kJ} \,\mathrm{~mol}^{-1}$

The magnitude of lattice enthalpy of $\mathrm{KCl}$ in $\mathrm{kJ} \mathrm{mol}^{-1}$ is ..... . (Nearest integer)

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