- A$Al_2O_3$
- B$AlF_3$
- ✓$AlCl_3$
- D$Al_2 (SO_4)_3$
$\mathrm{AlCl}_{3}$ is covalent due to the low difference in electronegativity.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{BrC{H_2} - CH - CO - C{H_2} - C{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{CON{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
is :
$(A)\,S_{\left( g \right)}^ - \,\, \to \,\,S_{\left( g \right)}^{2 - }\,$
$(B)\,Na_{\left( g \right)}^ + \, + \,Cl_{\left( g \right)}^ - \,\, \to \,\,NaCl\,(s)$
$(C)\,{N_{\left( g \right)}}\, \to \,\,N_{\left( g \right)}^ - $
$(D)\,Al_{\left( g \right)}^{2 + }\, \to \,\,Al_{\left( g \right)}^{3 + }$
Assertion $A$ : The stability order of +$1$ oxidation state of $\mathrm{Ga}$, In and $\mathrm{Tl}$ is $\mathrm{Ga}<\mathrm{In}<\mathrm{Tl}$.
Reason $R$ : The inert pair effect stabilizes the lower oxidation state down the group.
In the light of the above statements, choose the correct answer from the options given below :
Statement $I :$ $o-$Nitrophenol is steam volatile due to intramolecular hydrogen bonding.
Statement $II :$ $o-$Nitrophenol has high melting due to hydrogen bonding.
In the light of the above statements, choose the most appropriate answer from the options given below