MCQ
Which of the following is a polar compound
- ✓$HF$
- B$HCl$
- C$HN{O_3}$
- D${H_2}S{O_4}$
In $HF$ there is a much difference in the electronegatives of hydrogen and flourine. Therefore $(HF)$ is a polar compound.
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${ }^{-} \mathrm{OH}, \mathrm{R} \overline{\mathrm{O}}, \mathrm{CH}_3 \mathrm{CO} \overline{\mathrm{O}}, \mathrm{C} \overline{1}$
[Given : $R_{\mathrm{H}}\left(\right.$ Rydberg constant) $=2.18 \times 10^{-18} \mathrm{~J}$.
$h($ Plank's constant $)=6.6 \times 10^{-34}$ J.s. $]$