Question
Which of the following is a type of Linear programming problem?

Answer

  1. All of the above

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Choose the correct answer in Exercise:
If  $\text{f (a}+\text{b)}-\text{x}=\text{f (x)},$ then $\int^{\text{b}}_{\text{a}}\text{x f (x)}\ \text{dx}$  is equal to
  1. $\frac{\text{a}+\text{b}}{2}\int^{\text{a}}_{\text{b}}\text{f (b}-\text{x)}\text{dx}$
  2. $\frac{\text{a}+\text{b}}{2}\int^{\text{b}}_{\text{a}}\text{f (b}+\text{x)}\text{dx}$
  3. $\frac{\text{b}-\text{a}}{2}\int^{\text{b}}_{\text{a}}\text{f (x)}\text{dx}$
  4. $\frac{\text{a}+\text{b}}{2}\int^{\text{b}}_{\text{a}}\text{f (x)}\text{dx}$
The point which does not lie in the half plane $2 x+3 y-12 \leq 0$ is
If $\alpha,\beta,\gamma$ are the angle which a half ray makes with the positive directions of the axis then $\sin^2\alpha + \sin^2\beta + \sin^2\gamma =$
The point which lies in the half-plane $2 x+y-4 \leq 0$ is:
The equation xy = 0 in three dimensional space is represented by:
What is $ \tan ^{ -1 }{ \left( \frac { 1 }{ 2 } \right) } +\tan ^{ -1 }{ \left( \frac { 1 }{ 3 } \right) }$equal to?
  1. $ \frac { \pi }{ 3 }$
  2. $ \frac { \pi }{ 4 }$
  3. $ \frac { \pi }{ 6 }$
  4. $ \frac { \pi }{ 9 }$
Associated to a random experiment two events A and B are such that $\text{P(B)}=\frac{3}{5},\text{P}(\text{A}|\text{B})=\frac{1}{2}$ and $\text{P}(\text{A}\cup\text{B})=\frac{4}{5}$. The value pf P(A) is
  1. $\frac{3}{10}$
  2. $\frac{1}{2}$
  3. $\frac{1}{10}$
  4. $\frac{3}{5}$
Choose the correct answer from given four options in each of the Exercise:
If $\begin{vmatrix}2\text{x}&5\\8&\text{x}\end{vmatrix}=\begin{vmatrix}6&-2\\7&3\end{vmatrix},$ then value of x is:
  1. 3
  2. ±3
  3. ±6
  4. 6
Area bounded between the parabola $y^2 = 4ax$ and its latus rectum is$:$
The vector equation of the plane passing through $\vec{\text{a}},\ \vec{\text{b}},\ \vec{\text{c}},$ is $\vec{\text{r}}=\alpha\vec{\text{a}}+\beta\vec{\text{b}}+\gamma\vec{\text{c}}$, provided that,
  1. $\alpha+\beta+\gamma=0$
  2. $\alpha+\beta+\gamma=1$
  3. $\alpha+\beta=\gamma$
  4. $\alpha^2+\beta^2+\gamma^2=1$