(Equilibrium constants for the reaction in water and benzene are $K_{Water}$ $K_{Benzene}$)
$\mathrm{K}_{\text {Water }}<\mathrm{K}_{\text {Benzene }}$
$\therefore $ $(B)$ is correct answer.
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|
List$-I$ (Species) |
List$-II$ (Number of lone pairs of electrons on the central atom) |
| $(a)$ $\mathrm{XeF}_{2}$ | $(i)\, 0$ |
| $(b)$ $\mathrm{XeO}_{2} \mathrm{~F}_{2}$ | $(ii) \,1$ |
| $(c)$ $\mathrm{XeO}_{3} \mathrm{~F}_{2}$ | $(iii) \,2$ |
| $(d)$ $\mathrm{XeF}_{4}$ | $(iv) \,3$ |
Choose the most appropriate answer from the options given below:
