Download App

Equilibrium — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistryEquilibrium1 Mark
MCQ
Which of the following is correct regarding buffer sol?
  • A
    It contains a weak acid and its conjugate base.
  • B
    It contains a weak base and its conjugate acid.
  • C
    It shows little change in pH on adding small amount of acid or base.
  • D
    None of the above.
✓

Answer

  1. It shows little change in pH on adding small amount of acid or base.

Explanation:

A buffer solution shows little change in pH on adding small amount of acid or base.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Equilibrium→Equilibrium — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Bond angle of $H _2 O$ is :
→
$IUPAC$ name of the compound 
→
The solubility product of $AgI$ at $25\,^oC$ is $1.0 \times {10^{ - 16}}\,mo{l^2}\,{L^{ - 2}}$. The solubility if $AgI$ in ${10^{ - 4}}\,N$ solution of $KI$ at $25\,^oC$ is approximately (in $mol$ ${l^{ - 1}})$
→
Work done during isothermal expansion of one mole of $1$ mole of an ideal gas from $10$ $atm$ to $1$ atm at $300 \,K$  is.......$cal$ (Gas constant $= 2$ )
→
The number of given orbitals which have electron density along the axis is $..........$. $p _{ x }, p _{ y }, p _{ z }, d _{ xy }, d _{ yz }, d _{ xz }, d _z ^2, d _{ x ^2- y ^2}$
→
The correct order of priority. of groups $-SCH_3 \,(I), -NO_2\, (II), -C \equiv CH \,(III)$ and $-CH_2C_6H_5 \,(IV)$, on the basis of $CIP$ classification, is  (increasing order)
→
If in $NH_3$ formation $N$ uses its pure atomic orbital then wrong statement is
→
Lithium shows similarities to magnesium in its chemical behaviour because
→
Match the column $I$ with column $II$ and mark the appropriate choice
Column $I$ Column $II$
$(A)$ $CH_3COONa$ $(i)$ Almost neutral, $pH > 7$ or $< 7$
$(B)$ $NH_4Cl$ $(ii)$ Acidic, $pH < 7$
$(C)$ $NaNO_3$ $(iii)$ Alkaline, $pH > 7$
$(D)$ $CH_3COONH_4$ $(iv)$ Neutral, $pH = 7$
→
According to Le-chatelier's principle, an increase in the temperature of the following reaction will

${N_2} + {O_2}$ $\rightleftharpoons$ $2NO - 43,200\,kcal$

→