MCQ
Which of the following is correct ?
- ✓The members of $B_nH_{n+6}$ are less stable than $B_nH_{n+4}$ series
- BDiborane is coloured and unstable at room temperature
- CThe reaction of diborane with oxygen is endothermic
- DAll of the above
✓
Answer
Correct option: A.
The members of $B_nH_{n+6}$ are less stable than $B_nH_{n+4}$ series
a
The members of $B _{ n } H _{ n +6}$ are less stable than $B _{ n } H _{ n +4}$ series.
The members of $B _{ n } H _{ n +6}$ are less stable than $B _{ n } H _{ n +4}$ series.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
For the following reactions
→$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\mathrm{Z}^{-}$$\xrightarrow[{{\text{Sublimation}}}]{{{k_s}}} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Z}+\mathrm{Br}^{-}$
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\mathrm{Z}^{-}$$\xrightarrow[{{\text{elimination}}}]{{{k_e}}}\mathrm{CH}_{3} \mathrm{CH}= \mathrm{CH}_{2} +\mathrm{HZ}+\mathrm{Br}^{-}$
where
$\mathrm{Z}^{-}=\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}(\mathrm{A})$ or $\begin{array}{*{20}{c}}
{\,C{H_3}} \\
{|\,\,\,\,\,} \\
{C{H_3} - C - {O^ - }(B)} \\
{|\,\,\,\,} \\
{\,\,C{H_3}}
\end{array}$
$\mathrm{k}_{\mathrm{s}}$ and $\mathrm{k}_{\mathrm{e}},$ are $,$ respectively, the rate constants for the substitution and elimination, and $\mu=\frac{\mathrm{k}_{\mathrm{s}}}{\mathrm{k}_{\mathrm{e}}},$ the correct options is
Assertion : White phosphorus is more reactive than red phosphorus.
→Reason : Red phosphorus consists of $P_4$ tetrahedral units linked to one another to form linear chains.
Match List-$I$ with List-$II$
→| List-$I$ Species | List-$II$ Electronic distribution |
| $(A)$ $\mathrm{Cr}^{+2}$ | $(I)$ $3 \mathrm{~d}^8$ |
| $(B)$ $\mathrm{Mn}^{+}$ | $(II)$ $3 \mathrm{~d}^3 4 \mathrm{~s}^1$ |
| $(C)$ $\mathrm{Ni}^{+2}$ | $(III)$ $3\mathrm{~d}^4$ |
| $(D)$ $\mathrm{V}^{+}$ | $(IV)$ $3 \mathrm{~d}^5 4 \mathrm{~s}^1$ |
Choose the correct answer from the options given below:
The role of conc. ${H_2}S{O_4}$ in the esterification process is
→$4.5$ moles each of hydrogen and iodine heated in a sealed ten litre vessel. At equilibrium, $3$ moles of $HI$ were found. The equilibrium constant for ${H_2}_{(g)}+ {I_2}_{(g)}$ $\rightleftharpoons$ $2HI_{(g)}$ is
→The electron in the $n ^{\text {th }}$ orbit of $Li ^{2+}$ is excited to $(n+1)$ orbit using the radiation of energy $1.47 \times 10^{-17}\,J$ (as shown in the diagram). The value of $n$ is $....$.Given $R_H=2.18 \times 10^{-18}\,J$
→On heating ammonium dichromate and bariumazide separately we get
Ribose is an example of
In the series of reaction
→${C_6}{H_5}N{H_2}\mathop {\xrightarrow{{NaN{O_2}/HCl}}}\limits_{0 - 5\,^o C} X\mathop {\xrightarrow{{HN{O_2}}}}\limits_{C{H_2}O} Y + {N_2} + HCl$
$X$ and $Y$ are respectively
$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_3}\xrightarrow[{hv}]{{C{l_2}}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
→{C{H_3} - CH - C{H_2} - C{H_3}\xrightarrow[{hv}]{{C{l_2}}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
Number of chiral centers generated during monochlorination in the above reaction