MCQ
Which of the following is expected to be optically active
- A${(C{H_3})_4}C$
- ✓${C_2}{H_5}CH(C{H_3}){C_3}{H_7}$
- C${({C_2}{H_5})_2}CHC{H_3}$
- D$C{H_3}CH = CHC{H_3}$
✓
Answer
Correct option: B.
${C_2}{H_5}CH(C{H_3}){C_3}{H_7}$
b
As all the four substituents attached are different. So it is chiral and hence optical active.
As all the four substituents attached are different. So it is chiral and hence optical active.
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