MCQ
Which of the following is incorrect
- A$I^+ < I < I^-$ (Radii)
- B$CO, N_2, CN^-$ (Isoelectronic)
- ✓$F_2 > Cl_2 > Br_2 > I_2$ (Bond energy)
- D$Cl > F > Br > I$ (Electron Affinity)
✓
Answer
Correct option: C.
$F_2 > Cl_2 > Br_2 > I_2$ (Bond energy)
c
$Cl_2 > Br_2 > F_2 > I_2$ (Bond energy)
$Cl_2 > Br_2 > F_2 > I_2$ (Bond energy)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Major end product of the following sequence of reaction is:
→$CH_3CH_2CH_2CONH_2$ $\mathop {\xrightarrow{{Ca{{(OH)}_2},C{l_2}}}}\limits_\Delta X\xrightarrow{{HN{O_2}}}Z$
The number of unpaired electrons in $Ni{(CO)_4}$ is
→At $25\,^o C$, the dissociation constant of a base $BOH$ is $1.0 \times {10^{ - 12}}$. The concentration of Hydroxyl ions in $0.01\, M$ aqueous solution of the base would be
→$[Co(NH_3)Cl(en)_2]^{2+}$ shows two geometrical isomers cis and trans. Which of the following statements is correct ?
→According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as $(h = 6.62 \times 10^{-27} \ ergs,$$ \ c = 3 \times cm s^{-1}, $$\ N_A = 6.02 \times 10^{-23} \ mol^{-1})$
→The oxidation number of sulphur in ${H_2}{S_2}{O_7}$ and iron in ${K_4}Fe{(CN)_6}$ is respectively
→Which of following will give $N_2$ gas on treatment with nitrous acid :-
→$EAN$ of $Co$ in $Co_2(CO)_8$ will be
→The catalytic activity of the transition metal and their compound is due to their
The major product formed in the reaction is
