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Answer
Correct option: C.$3-$ methylheptane
c
(c) $\mathop {\mathop {C{H_3}CH_2^*CHC{H_2}C{H_2}C{H_3}}\limits^{|{\kern 1pt} \,\,\,\,\,\,{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} } }\limits^{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} } $ has a chiral carbon atom and hence is optically active.
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