MCQ
Which of the following is the correct reducing order of bond-angle
- A$N{H_3} < C{H_4} < {C_2}{H_2} < {H_2}O$
- ✓${C_2}{H_2} > N{H_3} > {H_2}O < C{H_4}$
- C$N{H_3} > {H_2}O > C{H_4} < {C_2}{H_2}$
- D${H_2}O < N{H_3} > C{H_4} < {C_2}{H_2}$
✓
Answer
Correct option: B.
${C_2}{H_2} > N{H_3} > {H_2}O < C{H_4}$
b
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