MCQ
Which of the following is the most basic oxide ?
- A$SeO_2$
- B$Al_2O_3$
- C$Sb_2O_3$
- ✓$Bi_2O_3$
So the basic nature is
$B i_{2} O_{3}>S b_{2} O_{3}>A l_{2} O_{3}>S e O_{2}$
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$\mathop { - CH{{(C{H_3})}_2}}\limits_1 \,\,\,\,\,\,\,\,\,\,\,\mathop { - C{H_2}C{H_2}Br}\limits_2 \,\,\,\,\,\,\,\,\,\,\mathop{ - C{H_2}Br}\limits_3 \,\,\,\,\,\,\,\,\,\mathop{ - C{{(C{H_3})}_3}}\limits_4$
$I = II = III = IV$
then which one is not correct
Kaushal's method : $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}\xrightarrow{{KCl}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
Preeti's method : $C{H_3} - CH = C{H_2}\xrightarrow{{C{l_2} + {H_2}O}}$
Raghav's method : $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}\xrightarrow[{Pyridine}]{{SOC{l_2}}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$