- A$\Delta H = 0$
- B$\Delta W = 0$
- ✓$\Delta Q = 0$
- D$\Delta V = 0$
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Which of the following product $(s)$ is/are can be obtained in the above reaction.
$(i)$ A $0.5\,m$ $NaBr$ solution has a higher vapour pressure than a $0.5\,m\,BaCl_2$ solution at the same temperature
$(ii)$ Pure water freezes at the higher temperature than pure methanol
$(iii)$ a $0.1\,m\,NaOH$ solution freezes at a lower temperature than pure water
Choose the correct answer from the codes given below
$X \left| X ^{2+}(0.001 M ) \| Y ^{2+}(0.01 M )\right| Y$
is $.......\times 10^{-2} V$ (Nearest integer).
Given: $E _{ x ^{2+} \mid x }^0=-2.36\,V$
$E _{ Y ^{3+} \mid Y }^0=+0.36\,V$
$\frac{2.303\,RT }{ F }=0.06\,V$
$E^o_{Fe^{3+} /Fe} = -0.036\,V,$ $E^o _{Fe^{2+} /Fe} = -0.439\,V$
The value of standard electrode potential for the change,
$Fe^{3+} (aq) + e^- \rightarrow Fe^{2+} (aq)$ will be ........ $V$.