MCQ
Which of the following metal is expected to have the highest third ionization enthalpy?
- A$Cr (Z=24)$
- B$V (Z=23)$
- ✓$Mn (Z=25)$
- D$Fe(Z=26)$
✓
Answer
Correct option: C.
$Mn (Z=25)$
c
The electronic configuration of these metals is:
The electronic configuration of these metals is:
$Cr :[\operatorname{Ar}]\, 3 d ^5 \,4 s ^1$
$V :[ Ar ] \,3 d ^3 \,4 s ^2$
$Mn :[ Ar ] \,3 d ^5 \,4 s ^2$
$Fe : [ Ar ]\, 3 d ^6\, 4 s ^2$
The third ionization enthalpy of $Mn$ means removal of electron from the stable configuration of $3 d ^5$. The metal having the highest third ionization enthalpy is $Mn.$
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