- ✓$Fe_2O_3$
- B$Pb_3O_4$
- C$Mn_2O_3$
- D$Sb_2O_3$
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$SO{{_{3}^{2-}}_{\left( aq. \right)}}+{{H}_{2}}{{O}_{\left( l \right)}}\to SO{{_{4}^{2-}}_{\left( aq. \right)}}+2{{H}^{+}}_{\left( aq. \right)}+2{{H}^{+}}_{\left( aq. \right)}+2{{e}^{-}}$
If the oxidation number of metal in the salt was $+3$, what would be the new oxidation number of metal?
$CH_3-COOH$ $\mathop {\xrightarrow{{(i)\,B{r_2}/P}}}\limits_{(ii)\,NaCN\,(iii)\,{H_2}O/{H^ \oplus }/\Delta } \,[X]$
$[X]$ will be :
| List-$I$ | List-$II$ | ||
| $A$ | $[Fe(H_2O)_6]^{2+}$ | $P$ | $0$ |
| $B$ | $[Fe(H_2O)_6]^{3+}$ | $Q$ | $1$ |
| $C$ | $[Fe(CN)_6]^{4-}$ | $R$ | $2$ |
| $D$ | $[Fe(CN)_6]^{3-}$ | $S$ | $4$ |
| $E$ | $[Ni(H_2O)_4]^{2+}$ | $T$ | $5$ |
$A$ $||$ $B$ $||$ $C$ $||$ $D$ $||$ $E$
$(1)$ It has $2$ angular nodes
$(2)$ It has $3$ radial nodes
$(3)$ It is a 4d state
$(4)$ The nuclear charge experienced by the electron in this state is less than $2 e$, where $e$ is the magnitude of the electronic charge.