$XeO _{3}, XeO _{2} F _{2}, XeO _{4}, XeO _{3} F _{2}, Ba _{2} XeF _{4}$
- ✓$2$
- B$3$
- C$4$
- Dzero
$XeO _{3}, XeO _{2} F _{2}, XeO _{4}, XeO _{3} F _{2}, Ba _{2} XeF _{4}$
Among the above shown compounds $XeO _{4},$ and $XeO _{3} F _{2}$ do not have lone pairs of electrons.
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$A ( g ) \rightleftharpoons B ( g )+\frac{1}{2} C ( g )$
the relation between dissociation constant ( $K$ ), degree of dissociation $(\alpha)$ and equilibrium pressure $(p)$ is given by?
${N_2}\left( g \right) + {O_2}\left( g \right)\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}2NO\left( g \right)$
$C_0 = Ce^{-2.1×10^{-3}\ t}$ for the forward reaction and
$C_0'= C'e^{-4.2×10^{-4}\ t}$ for the backward reaction, hence $K_c$ for the above equilibrium is
