- A$NaNO_3$
- ✓$AgNO_3$
- C$NH_4NO_3$
- D$NH_4NO_2$
${2 \mathrm{NaNO}_{3} \frac{500\,^{\circ} \mathrm{C}}{800\,^{\circ} \mathrm{C}} 2 \mathrm{NaNO}_{2}+\mathrm{O}_{2}} $
${4 \mathrm{NaNO}_{3} \stackrel{800\,^{\circ} \mathrm{C}}{\longrightarrow} 2 \mathrm{Na}_{2} \mathrm{O}+5 \mathrm{O}_{2}+2 \mathrm{N}_{2}}$
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$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - {C_6}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{HBr\,/\,Peroxide}}'A'$
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - {C_6}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{HBr}]{}'B'$


| $[HI]$, $M$ | rate, $Ms^{-1}$ |
| $0.0500$ | $8.80 \times {10^{ - 10}}$ |
| $0.1000$ | $3.52 \times {10^{ - 9}}$ |
| $0.1500$ | $7.92 \times {10^{ - 9}}$ |