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Statement $I$: The boiling point of hydrides of Group $16$ elements follow the order
$\mathrm{H}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{Te}>\mathrm{H}_2 \mathrm{Se}>\mathrm{H}_2 \mathrm{~S}$.
Statement $II$: On the basis of molecular mass, $\mathrm{H}_2 \mathrm{O}$ is expected to have lower boiling point than the othe members of the group but due to the presence of extensive $\mathrm{H}$-bonding in $\mathrm{H}_2 \mathrm{O}$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
$\left[ Ag \left( H _{2} O \right)_{2}\right]\left[ Ag ( CN )_{2}\right]$ is :
$(1)$ In gas phase $SO_2$ molecule is $V-$ shape.
$(2)$ In gas Phase $SO_3$ molecule is planar
$(3)$ $\gamma - SO_3$ is cyclic trimer
Which oi the above statement are correct ?