MCQ
Which of the following orders regarding relative stability of free radicals is correct
- A$3^° < 2^° < 1^°$
- ✓$3^° > 2^° > 1^°$
- C$1^° < 2^° > 3^°$
- D$3^° > 2^° < 1^°$
$3^\circ > 2^\circ > 1^\circ $.
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$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C{H_2} - C = C - CH - C - C{H_2} - C{H_2} - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,}\\
{{C_2}{H_5}}
\end{array}$
Given : $N -N =159\,kJ\,mol^{-1};\,\,H-H = 436\,kJ\,mol^{-1}$
$N \equiv N = {\text{ }}941{\text{ }}kJ{\text{ }}mo{l^{ - 1}}{\text{ }};{\text{ }}N-H{\text{ }} = {\text{ }}398{\text{ }}kJ{\text{ }}mo{l^{ - 1}}$ .....$kJ\,mol^{-1}$
