MCQ
Which of the following pair is expected to have the same bond order?
  • A
    $\text{O}_{2},\text{N}_{2}$
  • $\text{O}^{+}_{2},\text{N}^{-}_{2}$
  • C
    $\text{O}^{-}_{2},\text{N}^{+}_{2}$
  • D
    $\text{O}^{-}_{2},\text{N}^{-}_{2}$

Answer

Correct option: B.
$\text{O}^{+}_{2},\text{N}^{-}_{2}$
Bonad order $=\frac{(\text{N}_{\text{b}}-\text{N}_{\text{a}})}{2}$
In $O_2$ number of electrons in bonding orbitita are $10$ and are $5.$
Bonad order $=\frac{(10-5)}{2}=2.5$
In $N_2$ number of electrons $10$ and are $3.$

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