MCQ
Which of the following pair is expected to have the same bond order?
- A$\text{O}_{2},\text{N}_{2}$
- B$\text{O}^{+}_{2},\text{N}^{-}_{2}$
- C$\text{O}^{-}_{2},\text{N}^{+}_{2}$
- D$\text{O}^{-}_{2},\text{N}^{-}_{2}$
✓
Answer
- $\text{O}^{+}_{2},\text{N}^{-}_{2}$
Explantion
Bonad order $=\frac{(\text{N}_{\text{b}}-\text{N}_{\text{a}})}{2}$
In O2 number of electrons in bonding orbitita are 10 and are 5.
Bonad order $=\frac{(10-5)}{2}=2.5$
In N2 number of electrons 10 and are 3.
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