$\xrightarrow{{SOC{l_2}}}B\xrightarrow{{N{H_3}}}C\xrightarrow[{B{r_2}}]{{NaOH}}D$

image $\xrightarrow{{A{c_2}O}}A\mathop {\xrightarrow{{B{r_2}}}}\limits_{C{H_3}COOH} B\mathop {\xrightarrow{{{H_2}O}}}\limits_{{H^ + }} C$ would be
$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$(Yellow coloured compound)
Consider the above reaction, the Product $"P"$ is:
