7. Alcohol, phenol and ethers — Chemistry STD 12 Science — Question

$(I)$ the highest oxidation state of iron is $+ 6$ in $K_ 2FeO_4$

$(II)$ that the iron shows $+ 2$ oxidation state with six electrons in the $3d$ orbitals

$(III)$ the common oxidation state of iron is $+3$ with five unpaired electrons in $3d$ orbital

$Image$

In this reaction, $\mathrm{RCONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.

$1.$  How can the conversion of $(i)$ to $(ii)$ be brought about?

$(A)$ $\mathrm{KBr}$  $(B)$ $\mathrm{KBr}+\mathrm{CH}_3 \mathrm{ONa}$  $(C)$ $\mathrm{KBr}+\mathrm{KOH}$  $(D)$ $\mathrm{Br}_2+\mathrm{KOH}$

$2.$  Which is the rate determining step in Hofmann bromamide degradation?

$(A)$ Formation of $(i)$  $(B)$ Formation of $(ii)$  $(C)$ Formation of $(iii)$  $(D)$ Formation of $(iv)$

$3.$  What are the constituent amines formed when the mixture of $(i)$ and $(ii)$ undergoes Hofmann bromamide degradation?

$Image$

give the answer question $1$, $2$, and $3.$

$\mathop {(A)}\limits_{{C_{11}}{H_8}O}  \to $ does not under go self aldol condensation

$\mathop {(A)}\limits_{{C_{11}}{H_8}O} \xrightarrow{{{O_3}}}ph\, - \,CHO\, + \,2B\,\xrightarrow{{A{g^ + }}}$ Oxalic acid

$Xe{F_6}\,\xrightarrow{{ + {H_2}O}}A\,\xrightarrow{{ + {H_2}O}}B\,\xrightarrow{{ + {H_2}O}}C$