- A$PbO_2$
- ✓conc. $H_2SO_4$
- C$MnO_2$
- D$K_2Cr_2O_7/H^-$
$(a)$ $2{\text{HCl}} + {\text{Pb}}{{\text{O}}_2} \to {\text{PbO}} + {\text{C}}{{\text{l}}_2} \uparrow + {{\text{H}}_2}{\text{O}}$
$(b)$ $HCl + conc.{H_2}S{O_4} \to No\,reaction$
$(c)$ $4{\text{HCl}} + {\text{Mn}}{{\text{O}}_2} \to {\text{MnC}}{{\text{l}}_2} + 2C{l_2} \uparrow + 2{{\text{H}}_2}{\text{O}}$
$(d)$ $2{\text{HCl + }}{{\text{K}}_2}{\text{C}}{{\text{r}}_2}{{\text{O}}_7} + 12{{\text{H}}^ + } \to 2{\text{C}}{{\text{r}}^{3 + }}(aq.) + 2{{\text{K}}^ + }(aq.) + {\text{C}}{{\text{l}}_2} \uparrow + 7{{\text{H}}_2}{\text{O}}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
${\text{2PQ}} \rightleftharpoons {{\text{P}}_2}{\text{ + }}{{\text{Q}}_2}\,;\,\,\,\,{{\text{K}}_1}{\text{ = 2}}{\text{.5 }} \times \,{\text{1}}{{\text{0}}^5}\,$
${\text{PQ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,;\,\,\,\,{{\text{K}}_2}{\text{ = 5 }} \times \,{\text{1}}{{\text{0}}^{ - 3}}\,$
The value of equilibrium constant for reaction
$\frac{1}{2}{{\text{P}}_2}{\text{ + }}\frac{1}{2}{{\text{Q}}_2}{\text{ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,$ is
$PC{l_{3(g)}}\, + \,C{l_2}(g)\, \rightleftharpoons \,PC{l_{5(g)}}$
${H_2} + \frac{1}{2}{O_2} \to \,{H_2}O + 68.3\,kcal$
$C{H_4} + 2{O_2}\, \to \,C{O_2} + 2{H_2}O + 210.8\,kcal$ Then the possible heat of methane will be.....$ kcal$