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STD 12 - 2. Electrochemistry — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 2. Electrochemistry4 Marks
MCQ
Which of the following relation represents correct relation between standard electrode potential and equilibrium constant ?

$I$.  $\log \,\,K\, = \,\frac{{nF{E^o}}}{{2.303\,RT}}$

$II$.  $K\, = \,{e^{\frac{{nF{E^o}}}{{RT}}}}$

$III$.  $\log \,\,K\, = -\,\frac{{nF{E^o}}}{{2.303\,RT}}$

$IV$.  $\log \,\,K\, = 0.4342\,\,\frac{{-nF{E^o}}}{{RT}}$

Choose the correct statement $(s)$.

  • A
    $I,\, II$ and $III$ are correct
  • B
    $II$ and $III$ are correct
  • ✓
    $I,\, II$ and $IV$ are correct
  • D
    $I$ and $IV$ are correct
✓

Answer

Correct option: C.
$I,\, II$ and $IV$ are correct
c
$\Delta G\, = \, - \,2.303\,RT\,\log \,K$

$ - \,nF{E^o}\, = \, - \,2.303\,RT\,\log \,K$

$\log \,K\, = \,\frac{{nF{E^o}}}{{2.303\,RT}}$

$ = \,0.4342\,\frac{{nF{E^o}}}{{RT}}$     .....   $(i)$

$\ln \,K\, = \,\frac{{nF{E^o}}}{{RT}}$

$K\, = \,{e^{\frac{{nF{E^o}}}{{RT}}}}$      ....  $(ii)$

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