MCQ
Which of the following relations is correct
  • A
    $\sin 1 < \sin 1^\circ $
  • $\sin 1 > \sin 1^\circ $
  • C
    $\sin 1 = \sin 1^\circ $
  • D
    $\frac{\pi }{{180}}\sin \,\,\,1\, = \sin \,\,\,{1^o}$

Answer

Correct option: B.
$\sin 1 > \sin 1^\circ $
b
(b)The true relation is $\sin 1 > \sin 1^\circ $

Since value of $\sin \theta $ is increasing $\left[ {0 \to \frac{\pi }{2}} \right]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The sum of all $3 -$digit numbers less than or equal to $500,$ that are formed without using the digit $"1"$ and they all are multiple of $11 ,$ is ..... .
If $\sin \theta+\operatorname{cosec} \theta=2$, then $\sin ^2 \theta+\operatorname{cosec}^2 \theta$ is equal to
The number of square matrices of order $5$ with entries from the set $\{0,1\}$, such that the sum of all the elements in each row is $1$ and the sum of all the elements in each column is also $1$ , is
Let $\theta, \phi \in[0,2 \pi]$ be such that $2 \cos \theta(1-\sin \phi)=\sin ^2 \theta\left(\tan \frac{\theta}{2}+\cot \frac{\theta}{2}\right) \cos \phi-1, \tan (2 \pi-\theta)>0$ and $-1 < \sin \theta < -\frac{\sqrt{3}}{2}$. Then $\phi$ cannot satisfy

$(A)$ $0 < \phi<\frac{\pi}{2}$ $(B)$ $\frac{\pi}{2} < \phi<\frac{4 \pi}{3}$

$(C)$ $\frac{4 \pi}{3} < \phi<\frac{3 \pi}{2}$ $(D)$ $\frac{3 \pi}{2} < \phi < 2 \pi$

Find the equation of a circle with center $(0, 0)$ and radius $5:$
Let $P$ be a closed polygon with $10$ sides and $10$ vertices (assume that the sides do not intersect except at the vertices). Let $k$ be the number of interior angles of $P$ that are greater than $180^{\circ}$. The maximum possible value of $k$ is
Out of 30 consecutive integers, 2 are chosen at random. The probability that their sum is odd, is
The number of ways, in which $5$ girls and $7$ boys can be seated at a round table so that no two girls sit together, is
The sum to infinite term of the series $1 + \frac{2}{3} + \frac{6}{{{3^2}}} + \frac{{10}}{{{3^3}}} + \frac{{14}}{{{3^4}}} + \ldots \;$ is
Let $n$ be a positive integer. Let  $A =\sum_{ k =0}^{ n }(-1)^{ k } n _{ C _{ k }}\left[\left(\frac{1}{2}\right)^{ k }+\left(\frac{3}{4}\right)^{ k }+\left(\frac{7}{8}\right)^{ k }+\left(\frac{15}{16}\right)^{ k }+\left(\frac{31}{32}\right)^{ k }\right]$ . If $63 A =1-\frac{1}{2^{30}},$ then $n$ is equal to ...... .