MCQ
Which of the following requires radical intermediate
  • A
    $C{H_3} - CH = C{H_2} + HBr \to C{H_3} - \mathop {\mathop C\limits_| H}\limits_{Br\;}  - C{H_3}$
  • B

  • $C{{H}_{3}}-CH=C{{H}_{2}}+HBr\to C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br$
  • D
    $C{H_3}CHO + N{H_2}OH\xrightarrow{{{H^ + }}}C{H_3} - CH = N - OH$

Answer

Correct option: C.
$C{{H}_{3}}-CH=C{{H}_{2}}+HBr\to C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br$
c
It’s obvious.

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