MCQ
Which of the following sets of quantum numbers is correct for an electron in $4f$ orbital
  • $n = 4,\,l = 3,\,m = + 1,\,s = + \frac{1}{2}$
  • B
    $n = 4,\,l = 4,\,m = - 4,\,s = - \frac{1}{2}$
  • C
    $n = 4,\,l = 3,\,m = + 4,\,s = + \frac{1}{2}$
  • D
    $n = 3,\,l = 2,\,m = - 2,\,s = + \frac{1}{2}$

Answer

Correct option: A.
$n = 4,\,l = 3,\,m = + 1,\,s = + \frac{1}{2}$
a
(a) For $4f$ orbital electron, $n = 4$

$l = 3$ (Because $0, 1, 2, 3$)

        $s, p, d, f$

$m = + 3, + 2, +1, 0, -1, -2, -3$

$s = +1/2$

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