MCQ
Which of the following solution will exhibit highest boiling point
- A$0.01\,M\,Na_2SO_4$
- ✓$0.01\,M\,KNO_3$
- C$0.015\,M$ urea
- D$0.015\,M$ glucose
$\mathrm{H}^{+}=10^{-2}=\mathrm{C} \alpha(\text { mono-basic acid })$
${\alpha=\frac{10^{-2}}{0.1}=0.1} $
${\mathrm{i}=1+\alpha(\mathrm{N}-1)}$
${\mathrm{i}=1+0.1(2-1)}$
${\mathrm{i}=1.1}$
${\pi=0.1 \times \mathrm{RT} \times 1.1} $
${\pi=0.11\,\, \mathrm{RT}}$
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$CH_3CHO$ $\xrightarrow[{\left( {ii} \right)\,{H_2}O}]{{(i)\,C{H_3}MgBr}}A\xrightarrow[\Delta ]{{{H_2}S{O_4}}}B\xrightarrow[{Oxidation}]{{Hydroboaration}}C$
$Cu^{+2} +e^-\to Cu^+\,\,\,\,\,E^o = 0.15\,volt$
$Cu^{+2} + 2e^-\to Cu\,\,\,\,\,E^o = 0.34\, volt$
What will be the $E^o$ for half cell
$Cu^+ + e^-\to Cu$ ? ........... $\mathrm{volt}$