MCQ
Which of the following solution will exhibit highest boiling point
- A$0.01\,M\,Na_2SO_4$
- ✓$0.01\,M\,KNO_3$
- C$0.015\,M$ urea
- D$0.015\,M$ glucose
$\mathrm{H}^{+}=10^{-2}=\mathrm{C} \alpha(\text { mono-basic acid })$
${\alpha=\frac{10^{-2}}{0.1}=0.1} $
${\mathrm{i}=1+\alpha(\mathrm{N}-1)}$
${\mathrm{i}=1+0.1(2-1)}$
${\mathrm{i}=1.1}$
${\pi=0.1 \times \mathrm{RT} \times 1.1} $
${\pi=0.11\,\, \mathrm{RT}}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$A{l_{\left( s \right)}}|A{l^{ + 3}}\left( {0.1\,M} \right)||F{e^{ + 2}}\left( {0.001\,M} \right)|Fe\left( s \right)$ If $E_{A{l^{ + 3}}/Al}^o = - 1.66\,V$ and $E_{Fe/F{e^{ + 2}}}^o = + 0.44\,V$
