Download App

STD 11 - 2. structure of atom — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 2. structure of atom4 Marks
MCQ
Which of the following statement is not correct for an electron that has the quantum numbers $4 =$ and $m =2$
  • A
    then electron may have the quantum number $s = +1/2$
  • B
    the electron may have the quantum number $l = 2$
  • C
    the electron may have the quantum number $l = 3$
  • ✓
    the electron may have the quantum number $l = 0,1,2$ or $3$
✓

Answer

Correct option: D.
the electron may have the quantum number $l = 0,1,2$ or $3$
d
When $m =2,1$ cannot be $0$ or $1 .$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The De-broglie $\lambda$ of electron in the $2^{st}$ Bohr orbit is
→
$A [M(H_2O)_6]^{2+}$ complex typically absorbs at around $600\, nm$. It is  allowed to react with ammonia to form a new complex $[M(NH_3)_6]^{2+}$ that  should have absorption at ....... $nm$
→
Using anhydrous $AlC{l_3}$ as catalyst, which one of the following reaction produces ethylbenzene $(PhEt)$
→
In ${[NiC{l_4}]^{2 - }},$ the number of unpaired electron is
→
Product; Product is
→
The correct decreasing order in the enol 'content of following molecules is
→
The formula of potassiumdicyano bis (oxalato) nickelate $(II) $ is
→
In the given reaction :

$\begin{array}{*{20}{c}}
  O \\ 
  {||} \\ 
  {{C_6}{H_5} - C - C{H_3}} 
\end{array}\mathop {\xrightarrow{{(i)\,B{r_2}/KOH}}}\limits_{(ii)\,{H^ \oplus }} CHB{r_3} + [X]$

$[X]$ will be :

→
Delocalised molecular orbitals are found in
→
$CaCO_3 + 2HCl \to CaCl_2 + CO_2 + H_2O$ ; In this chemical reaction what will be the amount of calcium chloride when $10\,g$ calcium carbonate and $400\, mL\, 0.25\, M\, HCl$ is used .............. $\mathrm{g}$
→