- AAt room temperature, formyl chloride is present in the form of $CO$ and $HCl$
- BAcetamide behaves as a weak base as well as a weak acid
- C$CH_3CONH_2$ $\xrightarrow{\text{LiAl}{{\text{H}}_{4}}}$ $CH_3CH_2NH_2$
- ✓None of the three.
$(b)$ $C{H_3}CON{H_2}\,\xrightarrow{{HCl}}\,C{H_3}CO\mathop N\limits^ + {H_3}C{l^ - }$
$(c)$ $C{H_3}CON{H_2}$ $\xrightarrow[{or\,\,Na/{C_2}{H_5}OH}]{{LiAl{H_4}}}$ $C{H_3}C{H_2}N{H_2} + {H_2}O$
Thus all the three are correct.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\mathrm{Pt}(s) \mid \mathrm{H}_2(g, 1 \text { bar })\left|\mathrm{H}^{+}(a q, 1 \mathrm{M}) \| \mathrm{M}^{4+}(a q), \mathrm{M}^{2+}(a q)\right| \mathrm{Pt}(s)$
$E_{\text {cell }}=0.092 \mathrm{~V} \text { when } \frac{\left[\mathrm{M}^{2+}(a q)\right]}{\left[\mathrm{M}^{4+}(a q)\right]}=10^x$
Given : $ E_{\mathrm{M}^4 / \mathrm{M}^{2+}}^0=0.151 \mathrm{~V} ; 2.303 \frac{R T}{F}=0.059 \mathrm{~V}$
The value of $x$ is
$\underset{(1)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}{{O}^{-}}}}\,\,\,\,\,\,\underset{(2)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}{{S}^{-}}}}\,\,\,\,\underset{(3)}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,|| \\
C{{H}_{3}}C{{H}_{2}}C-{{O}^{-}} \\
\end{matrix}}}\,$
