- AAlkyl amines are stronger bases than aryl amines.
- BAlkyl amines react with nitrous acid to produce alcohols.
- ✓Aryl amines react with nitrous acid to produce phenols.
- DAlkyl amines are stronger bases than ammonia.
$(ii)$ $H NO_{2}$ converts $-N H_{2}$ group of aliphatic amine into$-OH$ while that of aromatic amines into $-N=N C$. Since, phenyl group is a electron withdrawing group, it decreases the basicity. Alkyl group, on the other hand, being electron releasing, increases the basicity. Thus, alkyl amines are more basic as compared to aryl amines as well as ammonia.
$R-N H_{2} \stackrel{H N O_{2}}{\longrightarrow} R-O H$
Thus, $H NO_{2}$ (nitrous acid) converts alkyl amines to alcohols. But aryl amines react with nitrous acid to form diazonium salt.
$\quad C_{6} H_{5} N H_{2} \frac{H N O_{2}}{0.5\,^{o} C(273-278 \,K)} C_{6} H_{5}-N_{2}^{+} C l$ at $0.5\,^{o} \mathrm{C}$
temperature
$\mathrm{NaNO}_{2}+\mathrm{HCl} \longrightarrow \mathrm{HNO}_{2}+\mathrm{NaCl},$
Thus $\mathrm{HNO}_{2}$ does not convert aryl amines into phenol.
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The standard potential for this reaction is $0.46\, V$ which change will increase the potential the most?
| List-l (Compounds) | List-II (Reactions) |
a. ![]() | i. Gives red colouration in victor Meyer's test |
b.![]() | ii. Produces immediate turbidity with Luca's reagent |
| C. CH2CH2CHO | iii. Forms white precipitate with bromine water |
| d . C6H5CH2OH | iv. Forms silver mirror on reaction with ammoniacal AgNO3 solution. |