- A${C_2}{H_5}Br$ reacts with alco. $KOH$ to form ${C_2}{H_5}OH$
- B${C_2}{H_5}Br$ when treated with metallic sodium gives ethane
- C${C_2}{H_5}Br$ when treated with sodium ethoxide forms diethyl ether
- ✓Both $(a)$ and $(b)$
${C_2}{H_5}\,\boxed{Br + 2Na + Br} - {C_2}{H_5} \to \mathop {{C_2}{H_5} - {C_2}{H_5}}\limits_{{\text{Butane}}} + 2NaBr$
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$Cl_2(aq) + H_2S(aq) \to S(s) + 2H^+(aq) + 2Cl^-(aq)$ rate law is $r = K[Cl_2][H_2S]$
then which of these mechanism is/are consistent with this rate law
$(A)\, H_2S \rightleftharpoons H^+ + HS^-$ (fast)
$Cl_2 + HS^-\to 2Cl^-+ H^+ + S$ (slow)
$(B)\, Cl_2 + H_2S \to H^+ + Cl^-+ Cl^+ + HS^-$ (slow)
$Cl^+ + HS^-\to H^+ + Cl^-+ S$ (fast)
The molar mass difference between compounds $Q$ and $R$ is $474 \mathrm{~mol}^{-1}$ and between compounds $P$ and $S$ is $172.5 \mathrm{~g} \mathrm{~mol}^{-1}$.
($1$)The number of heteroatoms present in one molecule of $R$ is. . . . . .
[Use: Molar mass (in g mol ${ }^{-1}$ ): $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$
Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms]
($2$)The total number of carbon atoms and heteroatoms present in one molecule of $S$. . . . . .
[Use: Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ ]: $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$
Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms
Give the answer quetion ($1$) and ($2$)
$CHC{l_3}\xrightarrow{{Air/hv}}x\xrightarrow[{Excess}]{{{C_6}{H_6}\,/\,Anhy\,AlC{l_3}}}y$ , $y$ will be