MCQ
Which of the following transformation least energy is required?
  • A
    $F^-_{(g)} \to F_{(g)} +e^-$
  • $P^-_{(g)} \to P_{(g)} +e^-$
  • C
    $S^-_{(g)} \to S_{(g)} +e^-$
  • D
    $Cl^-_{(g)} \to Cl_{(g)} +e^-$

Answer

Correct option: B.
$P^-_{(g)} \to P_{(g)} +e^-$
b
$(b)$ If we consider the opposite process :
$(a)\, F_{(g)} +e^- \to F^-_{(g)}\,\,\,\,\,\,\,\,\, ; \,\,\,\,\,\,\,\, \Delta H_1$

$(b)\, P_{(g)} +e^- \to P^-_{(g)}\,\,\,\,\,\,\,\,\, ; \,\,\,\,\,\,\,\, \Delta H_2$ 

$(c)\, S_{(g)} +e^- \to S^-_{(g)}\,\,\,\,\,\,\,\,\, ; \,\,\,\,\,\,\,\, \Delta H_3$ 

$(d)\, Cl_{(g)} +e^- \to Cl^-_{(g)}\,\,\,\,\,\,\,\,\, ; \,\,\,\,\,\,\,\, \Delta H_4$ 

Order of energy releases Is : $\Delta H_4 > \Delta H_1 > \Delta H_3 > \Delta H_2$

So,  $P^-_{(g)} \to P_{(g)} + e^- ;$  Requires least energy.

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