MCQ
Which of the following will be chiral
- A$C{H_3}CHC{l_2}$
- ✓$C{H_3}CHBrCl$
- C$C{D_2}C{l_{_2}}$
- D$C{H_2}ClBr$
✓
Answer
Correct option: B.
$C{H_3}CHBrCl$
b
(b) $\mathop {\mathop {\mathop {\mathop {Br - {C^*} - Cl}\limits^| }\limits^{\,\,\,\,\,\,\,C{H_3}} }\limits_| }\limits_H $ * asymmetric or chiral carbon
(b) $\mathop {\mathop {\mathop {\mathop {Br - {C^*} - Cl}\limits^| }\limits^{\,\,\,\,\,\,\,C{H_3}} }\limits_| }\limits_H $ * asymmetric or chiral carbon
All the four valencies of carbon are satisfied with different atoms/substituents.
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Consider the following reactions
→$(a)\;\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}(\mathrm{OH}) \mathrm{CH}_{3} \stackrel{\mathrm{conc.H}, \mathrm{SO}_{4}}{\longrightarrow}$
$(b)\;\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}(\mathrm{Br}) \mathrm{CH}_{3} \stackrel{\text { alc.KOH }}{\longrightarrow}$
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{{{(C{H_3})}_2}C - C{H_2} - CHO} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{\Delta }$
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