MCQ
Which of the following will not give Hoffmann bromamide reaction ?
  • A
    $\begin{matrix}
       O  \\
       ||  \\
       C{{H}_{3}}-C-N{{H}_{2}}  \\
    \end{matrix}$
  • B
    $\begin{matrix}
       O\,  \\
       ||\,\,  \\
       Ph-C-N{{H}_{2}}  \\
    \end{matrix}$
  • C
    $\begin{matrix}
       O\,\,\,\,\,\,\,\,  \\
       ||\,\,\,\,\,\,\,\,\,\,  \\
       C{{H}_{3}}-C-NH-Br  \\
    \end{matrix}$
  • $\begin{matrix}
       O\,\,\,\,\,\,\,\,\,\,\,  \\
       ||\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
       Ph-C-NH-Ph  \\
    \end{matrix}$

Answer

Correct option: D.
$\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   Ph-C-NH-Ph  \\
\end{matrix}$
d
$(d)$ $\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   Ph-C-NH-Ph  \\
\end{matrix}$ 

$N-$ substituted amide will not undergo Hoffmann bromamide reaction because  formation of iso- cyanate is not possible.

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