- AEthanal
- BEthanol
- C$2-$propanone
- ✓$3-$pentanone
group
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$F{e^{2 + }} + 2{e^ - } \to Fe( - 0.44\,V)$
$N{i^{2 + }} + 2{e^ - } \to Ni( - 0.25\,V)$
$S{n^{2 + }} + 2{e^ - } \to Sn( - 0.14V)$
$F{e^{3 + }} + {e^ - } \to F{e^{2 + }}( - 0.77\,V)$
The molar mass difference between compounds $Q$ and $R$ is $474 \mathrm{~mol}^{-1}$ and between compounds $P$ and $S$ is $172.5 \mathrm{~g} \mathrm{~mol}^{-1}$.
($1$)The number of heteroatoms present in one molecule of $R$ is. . . . . .
[Use: Molar mass (in g mol ${ }^{-1}$ ): $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$
Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms]
($2$)The total number of carbon atoms and heteroatoms present in one molecule of $S$. . . . . .
[Use: Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ ]: $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$
Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms
Give the answer quetion ($1$) and ($2$)